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WASHINGTON D. C. GEOMETRY

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Author Topic: WASHINGTON D. C. GEOMETRY  (Read 1850 times)
Seer of Dark Things
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« on: May 25, 2008, 04:02:46 am »

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The boundaries of the District of Columbia, established by George Washington in 1791, formed a square with sides ten miles long, centered on the originally proposed location for the Washington Monument. The east-west diagonal of the square also crosses over the Capitol building and the north-south diagonal also crosses over the White House as well as the Masonic headquarters.


James Clements' map of Washington City

The length of the north-south and east-west diagonals is ten miles times the square root of two, or 14.142 miles. This distance converts to 43,455 ancient Egyptian royal cubits, the same figure as the ratio between the Great Pyramid and the dimensions of the earth. The height of the Great Pyramid is 481.13 feet, divided by 5280 equals .0911231 miles. The mean radius of the earth is 3,960 miles, divided by .0911231 equals 43,457. The perimeter of the Great Pyramid is 3023 feet, divided by 5280 equals .5725 miles. The mean circumference of the earth is 24,880 miles, divided by .5725 = 43,458.

3960 miles (radius of the earth) divided by 14.142 miles = 280 (number of cubits in the height of the Great Pyramid)

24,880 miles (circumference of the earth) divided by 14.142 miles = 1,760 (cubits in the perimeter of the Great Pyramid)

Converting the radius and circumference of the earth to cubits yields the same results:

3,960 miles times 5,280 = 20,908,800 feet divided by 1.718 = 12,170,430 (earth radius in ancient Egyptian cubits)

12,170,430 cubits divided by 43,455 cubits = 280 cubits

24,880 miles times 5,280 = 131,366,400 feet divided by 1.718 = 76,464,726 (circumference in ancient Egyptian cubits)

76,464,726 cubits divided by 43,455 cubits = 1,760 cubits

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